The minimum time T_min and length λ_min

If we consider as a minimal quantity of time, time Tmin in which light would cover distance equal with length = 6,626026 ×10^-34 or would acquire the minimal quantity of energy h▪ 1Hz then we find :

2,997924 ×10⁸ m      in       1 sec

6,62606 ×10^-34 m       what sec ?

Tmin = λ / c = 2,210216 × 10^-42 → Tmin × c = h = λmin

If Tmin = 2,210216 × 10^-42  then  fmax = 1/Tmin = 0,452444 ×10⁴²

The time Tmin in which light would cover distance equal with length h= 6,626026 ×10^-34 m or would acquire the minimal quantity of energy h▪ 1Hz is Tmin = λmin/c gives a frequency fmax = 0,452444 ×10⁴² Hz.

Example with the length λ=0,24263 ×10^-11 m of the electron: In how much time t light would cover distance of length λe = 0,24263 ×10^-11 m.

Answer: Time t= 1 × λe/c = 0,0809326 ×10^-19 sec = 1/fe . It's ok.

Reminder: The constant length that is contained in the constant speed of light c is a length S=2,997924 ×10⁸ m. This length via the 2pi gives a radius r. That is to say 2,997924 ×10⁸ m / 6,283185 = 0,4771344 ×10⁸ m. This radius rc = 0,4771344 ×10⁸ m divided with the quantity hbar as an elementary length of radius gives us a ratio 0,4771344 ×10⁸ / 1,0545715 ×10^-34 = 0,452444 ×10⁴² .

Also, with the logic that the quantity h/2π is an elementary radius r that when it divides the biggest speed of light c (c/hbar) gives us result an angular velocity ω .The angular velocity ω/2π = frequency f. With the logic of this observation it results again as length of wave λ the constant action h and as a biggest frequency fmax = 0,452444 ×10⁴² Hz.

The same frequency fmax = 0,452444 ×10⁴² Hz results from the magnetic penetrability μ_ο =12,56636 ×10^-7 Henry /m and dielectric constant ε_o= 8,854 ×10^-12 Farad /m of empty (free) space, when we consider that the constant Plank h coincides with a fundamental length λmin = 6,62606 ×10^-34 m and applying relation V_c =1/ √μο εο and the main type of co-ordination in the electrotechnics T= 2π √L C :

μο λ_min = 83,265508 ×10^-41 Henry

εο λ_min = 58,667135 × 10^-46 Farad

(83,26550 ×10^-41 ) (58,66713 ×10^-46 )=4884,95 ×10^-87 (Henry × Farad = sec² )

√4,88495 ×10^-84 = 2,2102 × 10^-42 sec  and  1/2,2102 × 10^-42 = 0,45244 ×10⁴² Hz

For the formula T= 2π √L C we consider that length λ_min = h_bar 2pi

NEW LIMITS result with the scenario that constant h it is also length of wave λ. The limits fmax, Emax, Mmax, Tmin are suspect very near the maximum limits which result from mass and the energy Planck, the constant of unified constants Mpl = √ h c /G  (Mpl ≈ 5,45624 ×10^-8 kg). λ_min / λ_planck = 16,3574