If we consider as a minimal
quantity of time, time Tmin in which light would cover distance equal
with length = 6,626026 ×10^{34} or would acquire the minimal
quantity of energy h▪ 1Hz then we find :
2,997924 ×10^{8} m in
1
sec
6,62606
×10^{34} m what sec ?
Tmin = λ / c = 2,210216 × 10^{42} →
Tmin
× c = h = λmin
If Tmin = 2,210216 × 10^{42}
then
fmax = 1/Tmin = 0,452444 ×10^{42}
The time Tmin in which light
would cover distance equal with length h= 6,626026 ×10^{34} m or
would acquire the minimal quantity of energy h▪ 1Hz is Tmin = λmin/c
gives a frequency fmax = 0,452444 ×10^{42} Hz.
Example with the length
λ=0,24263 ×10^{11} m of the electron: In how much time t light
would cover distance of length λe = 0,24263 ×10^{11}
m.
Answer: Time t= 1 × λe/c
= 0,0809326 ×10^{19} sec = 1/fe . It's ok.
Reminder: The constant length that is
contained in the constant speed of light c is a length S=2,997924 ×10^{8}
m. This length via the 2pi gives a radius r. That is to
say 2,997924 ×10^{8} m / 6,283185 = 0,4771344 ×10^{8} m. This
radius rc
= 0,4771344 ×10^{8} m divided with the quantity hbar as an elementary
length of radius gives us a ratio 0,4771344 ×10^{8} / 1,0545715 ×10^{34}
= 0,452444 ×10^{42} .
Also, with the logic that the quantity
h/2π
is an elementary radius r that when it divides the biggest speed of light c
(c/hbar)
gives us result an angular velocity ω .The angular
velocity ω/2π
= frequency f.
With the logic of
this observation it results again as length of wave λ
the constant action h and as a biggest frequency fmax =
0,452444 ×10^{42} Hz.
The same frequency fmax =
0,452444 ×10^{42} Hz results from the magnetic penetrability
μ_{ο} =12,56636 ×10^{7} Henry /m and dielectric constant
ε_{o}= 8,854 ×10^{12} Farad /m of empty
(free) space, when we consider that the constant Plank h coincides with a
fundamental length λmin = 6,62606 ×10^{34}
m
and applying relation
V_{c} =1/ √μο εο
and the main type of coordination in the electrotechnics
T= 2π √L C :
μο λ_{min}
= 83,265508 ×10^{41 }Henry
εο λ_{min}
= 58,667135 × 10^{46} Farad
(83,26550 ×1041
) (58,66713 ×1046
)=4884,95 ×10^{87} (Henry × Farad = sec^{2} )
√4,88495
×10^{84} = 2,2102 × 10^{42} sec
and 1/2,2102 × 10^{42} =
0,45244 ×10^{42} Hz
For the formula T= 2π √L C we consider that
length λ_{min} = h_{bar} 2pi
NEW LIMITS result with the
scenario that constant h it is also length of wave λ.
The limits fmax, Emax, Mmax, Tmin are suspect very near the maximum limits
which result from mass and the energy Planck, the constant of unified constants Mpl
= √ h c /G (Mpl
≈ 5,45624 ×10^{8} kg). λ_{min} /
λ_{planck} = 16,3574
