If we consider as a __minimal
quantity of time, time __**Tmin** in which light would cover distance equal
with length = 6,626026 ×10^{-34} or would acquire the minimal
quantity of energy h▪ 1Hz then we find :

2,997924 ×10^{8} m in 1
sec

6,62606
×10^{-34} m what sec ?

**T**min = λ / c = 2,210216 × 10^{-42} →
**T**min × **c** =
**h** = **λ**min

If **T**min = 2,210216 × 10^{-42}
then **f**max = 1/**T**min = 0,452444 ×10^{42}

__The time Tmin in which light
would cover distance equal with length h= 6,626026 ×10__^{-34} m or
would acquire the minimal quantity of energy h▪ 1Hz is Tmin = λmin/c
gives a frequency fmax = 0,452444 ×10^{42} Hz.

Example with the length λ=0,24263 ×10^{-11} m of the electron: In how much time t light
would cover distance of length λe = 0,24263 ×10^{-11}
m.

Answer: Time t= 1 × λe/c
= 0,0809326 ×10^{-19} sec = 1/fe . It's ok.

Reminder: The constant length that is
contained in the constant speed of light **c** is a length S=2,997924 ×10^{8}
m. This length via the 2pi gives a radius **r**. That is to
say **2,997924 ×10**^{8} m / 6,283185 = 0,4771344 ×10^{8} m. This
radius **r**c
= 0,4771344 ×10^{8} m divided with the quantity **h**bar as an elementary
length of radius gives us a ratio **0,4771344 **×**10**^{8} / 1,0545715 ×10^{-34} =** 0,452444 **×**10**^{42} .

Also, with the logic that the quantity
h/2π
is an elementary radius **r** that when it divides the biggest speed of light **c**
(c/hbar)
gives us result an angular velocity **ω** .The angular
velocity ω/2π
= frequency f.
With the logic of
this observation it results again as length of wave **λ**
the constant action **h** and as a biggest frequency **f**max = **0,452444 **×**10**^{42} Hz.

The same frequency **f**max = **0,452444 ×10**^{42} Hz results from the magnetic penetrability
**μ**_{ο} =**12,56636 ×10**^{-7} Henry /m and dielectric constant
**ε**_{o}= **8,854 ×10**^{-12} Farad /m of empty
(free) space, when we consider that the constant Plank **h** coincides with a
fundamental length **λ**min = 6,62606 ×10^{-34}
m
and applying relation V_{c} =1/ √μο εο
and the main type of co-ordination in the electrotechnics
T= 2π √L C :

**μ**ο **λ**_{min}
= 83,265508 ×10^{-41 }**H**enry

**ε**ο **λ**_{min}
= 58,667135 × 10^{-46} **F**arad

(83,26550 ×10^{-41} ) (58,66713 ×10^{-46} )=4884,95 ×10^{-87} (Henry × Farad = sec^{2} )

√4,88495
×10^{-84} = **2,2102 × 10**^{-42} sec
and 1/2,2102 × 10^{-42} =
**0,45244 ×10**^{42} Hz

For the formula T= 2π √L C we consider that
length λ_{min} = h_{bar} 2pi

**NEW LIMITS** result with the
scenario that constant **h** it is also length of wave λ.
The limits fmax, Emax, Mmax, Tmin are __suspect__ very near the maximum limits
which result from mass and the energy Planck, the constant of unified constants **M**pl
=** √ h c /G** (Mpl
≈ 5,45624 ×10^{-8} kg). λ_{min} /
λ_{planck} = 16,3574